2x+x+1+x^2=336

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Solution for 2x+x+1+x^2=336 equation:



2x+x+1+x^2=336
We move all terms to the left:
2x+x+1+x^2-(336)=0
We add all the numbers together, and all the variables
x^2+3x-335=0
a = 1; b = 3; c = -335;
Δ = b2-4ac
Δ = 32-4·1·(-335)
Δ = 1349
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1349}}{2*1}=\frac{-3-\sqrt{1349}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1349}}{2*1}=\frac{-3+\sqrt{1349}}{2} $

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